整理代码

util/xpack/xml.h

@@ -0,0 +1,79 @@
+/*
+* Copyright (C) 2021 Duowan Inc. All rights reserved.
+*
+* Licensed under the Apache License, Version 2.0 (the "License");
+* you may not use this file except in compliance with the License.
+* You may obtain a copy of the License at
+*
+*    http://www.apache.org/licenses/LICENSE-2.0
+*
+* Unless required by applicable law or agreed to in writing,
+* software distributed under the License is distributed on an "AS IS" BASIS,
+* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
+* See the License for the specific language governing permissions and
+* limitations under the License.
+*/
+
+#ifndef __X_PACK_XML_H
+#define __X_PACK_XML_H
+
+#include "xml_decoder.h"
+#include "xml_encoder.h"
+#include "xpack.h"
+
+namespace xpack {
+/*
+for xml like
+<user>
+    <name>Pony</name>
+    <age>20</age>
+</user>
+
+Just define such a structure
+struct User {
+    string name;
+    int age;
+    XPACK(O(name, age));
+};
+
+!!!!NO NEED!!! to define:
+struct Data {
+    User user;
+    XPACK(O(user));
+};
+
+xml::decode will skip the root node, so for the xml defined above,
+it only needs to be decode like this:
+User u;
+xpack::xml::decode(str, u);
+*/
+
+class xml {
+public:
+    template <class T>
+    static void decode(const std::string &data, T &val) {
+        XmlDecoder de;
+        de.decode(data, val);
+    }
+    template <class T>
+    static void decode_file(const std::string &file_name, T &val) {
+        XmlDecoder de;
+        de.decode_file(file_name, val);
+    }
+    template <class T>
+    static std::string encode(const T &val, const std::string&root) {
+        XmlEncoder en;
+        return en.encode(val, root);
+    }
+
+    template <class T>
+    static std::string encode(const T &val, const std::string&root, int flag, int indentCount, char indentChar) {
+        (void)flag;
+        XmlEncoder en(indentCount, indentChar);
+        return en.encode(val, root);
+    }
+};
+
+}
+
+#endif