79 lines
No EOL
1.9 KiB
C++
Executable file
79 lines
No EOL
1.9 KiB
C++
Executable file
/*
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* Copyright (C) 2021 Duowan Inc. All rights reserved.
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*
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* Licensed under the Apache License, Version 2.0 (the "License");
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* you may not use this file except in compliance with the License.
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* You may obtain a copy of the License at
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*
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* http://www.apache.org/licenses/LICENSE-2.0
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*
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* Unless required by applicable law or agreed to in writing,
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* software distributed under the License is distributed on an "AS IS" BASIS,
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* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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* See the License for the specific language governing permissions and
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* limitations under the License.
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*/
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#ifndef __X_PACK_XML_H
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#define __X_PACK_XML_H
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#include "xml_decoder.h"
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#include "xml_encoder.h"
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#include "xpack.h"
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namespace xpack {
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/*
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for xml like
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<user>
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<name>Pony</name>
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<age>20</age>
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</user>
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Just define such a structure
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struct User {
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string name;
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int age;
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XPACK(O(name, age));
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};
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!!!!NO NEED!!! to define:
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struct Data {
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User user;
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XPACK(O(user));
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};
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xml::decode will skip the root node, so for the xml defined above,
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it only needs to be decode like this:
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User u;
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xpack::xml::decode(str, u);
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*/
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class xml {
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public:
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template <class T>
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static void decode(const std::string &data, T &val) {
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XmlDecoder de;
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de.decode(data, val);
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}
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template <class T>
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static void decode_file(const std::string &file_name, T &val) {
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XmlDecoder de;
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de.decode_file(file_name, val);
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}
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template <class T>
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static std::string encode(const T &val, const std::string&root) {
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XmlEncoder en;
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return en.encode(val, root);
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}
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template <class T>
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static std::string encode(const T &val, const std::string&root, int flag, int indentCount, char indentChar) {
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(void)flag;
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XmlEncoder en(indentCount, indentChar);
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return en.encode(val, root);
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}
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};
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}
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#endif |